(A) The given rate law is $\text{rate} = k[A]^2[B]$.Rearranging for the rate constant $k$,we get $k = \frac{\text{rate}}{[A]^2[B]}$.Substituting the g

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$4.8 \ mol^{-2} \ dm^6 \ s^{-1}$

(A) The given rate law is $\text{rate} = k[A]^2[B]$.Rearranging for the rate constant $k$,we get $k = \frac{\text{rate}}{[A]^2[B]}$.Substituting the given values: $k = \frac{0.24 \ mol \ dm^{-3} \ s^{-1}}{(0.5 \ mol \ dm^{-3})^2 \times (0.2 \ mol \ dm^{-3})}$.$k = \frac{0.24}{0.25 \times 0.2} = \frac{0.24}{0.05} = 4.8 \ mol^{-2} \ dm^6 \ s^{-1}$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

For the reaction $2A + 2B \rightarrow 2C + D$,the rate law is expressed as $\text{rate} = k[A]^2[B]$. Calculate the rate constant if the rate of reaction is $0.24 \ mol \ dm^{-3} \ s^{-1}$ where $[A] = 0.5 \ M$ and $[B] = 0.2 \ M$.

MHT CET 2023 All MHT CET

A
$4.8 \ mol^{-2} \ dm^6 \ s^{-1}$
B
$9.6 \ mol^{-2} \ dm^6 \ s^{-1}$
C
$12.1 \ mol^{-2} \ dm^6 \ s^{-1}$
D
$14.4 \ mol^{-2} \ dm^6 \ s^{-1}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

Previous Year

MHT CET 2023 Paper All MHT CET years →

The reaction $2FeCl_3 + SnCl_2 \to 2FeCl_2 + SnCl_4$ is an example of

MediumAIPMT 1996

View Solution

For the reaction $A + B \to \text{products}$,it is found that the rate of the reaction is proportional to the concentration of $A$,but it is independent of the concentration of $B$. Then:

Medium

View Solution

For a reaction,$A + B \longrightarrow$ Product; the rate law is given by $r = k[A]^2[B]^{1/2}$. What is the order of the reaction?

Medium

View Solution

For the reaction $A + B \rightarrow$ products,doubling the concentration of $A$ increases the reaction rate by four times,but doubling the concentration of $B$ has no effect on the reaction rate. What is the rate law?

Medium

View Solution

Inversion of cane sugar in dilute acid (conversion into glucose and fructose) is a:

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For the reaction $2A + 2B \rightarrow 2C + D$,the rate law is expressed as $\text{rate} = k[A]^2[B]$. Calculate the rate constant if the rate of reaction is $0.24 \ mol \ dm^{-3} \ s^{-1}$ where $[A] = 0.5 \ M$ and $[B] = 0.2 \ M$.

Similar Questions

The reaction $2FeCl_3 + SnCl_2 \to 2FeCl_2 + SnCl_4$ is an example of

For the reaction $A + B \to \text{products}$,it is found that the rate of the reaction is proportional to the concentration of $A$,but it is independent of the concentration of $B$. Then:

For a reaction,$A + B \longrightarrow$ Product; the rate law is given by $r = k[A]^2[B]^{1/2}$. What is the order of the reaction?

For the reaction $A + B \rightarrow$ products,doubling the concentration of $A$ increases the reaction rate by four times,but doubling the concentration of $B$ has no effect on the reaction rate. What is the rate law?

Inversion of cane sugar in dilute acid (conversion into glucose and fructose) is a:

Vedclass Test Series

Exam Paper Generator

Online Exam Module