For the reaction CH_3-CH=CH_2 + HOCl to A,the | vedclass

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Question

(B) The addition of $HOCl$ to propene follows Markovnikov's rule.$HOCl$ dissociates as $HO^{\delta-} - Cl^{\delta+}$.The electrophile $Cl^{+}$ attacks

Vedclass · Accepted Answer

$CH_3-CH(OH)-CH_2Cl$

Vedclass · Answer

(B) The addition of $HOCl$ to propene follows Markovnikov's rule.$HOCl$ dissociates as $HO^{\delta-} - Cl^{\delta+}$.The electrophile $Cl^{+}$ attacks the double bond to form a cyclic chloronium ion intermediate.The nucleophile $OH^{-}$ then attacks the more substituted carbon atom $(C-2)$ to open the ring.Thus,the reaction is: $CH_3-CH=CH_2 + HOCl 	o CH_3-CH(OH)-CH_2Cl$.Therefore,Option $B$ is the correct answer.

For the reaction $CH_3-CH=CH_2 + HOCl \to A$,the product $A$ is:

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