For the reaction 2 A + 3 B + frac{3}{2} C rig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a general reaction $a A + b B + c C ightarrow d P$,the rate of reaction is given by: $	ext{Rate} = -\frac{1}{a} \frac{dn_A}{dt} = -\frac{1}

Vedclass · Accepted Answer

$\frac{dn_A}{dt} = \frac{2}{3} \frac{dn_B}{dt} = \frac{4}{3} \frac{dn_C}{dt}$

Vedclass · Answer

(B) For a general reaction $a A + b B + c C ightarrow d P$,the rate of reaction is given by: $	ext{Rate} = -\frac{1}{a} \frac{dn_A}{dt} = -\frac{1}{b} \frac{dn_B}{dt} = -\frac{1}{c} \frac{dn_C}{dt} = \frac{1}{d} \frac{dn_P}{dt}$ Given the reaction $2 A + 3 B + \frac{3}{2} C ightarrow 3 P$,we have: $-\frac{1}{2} \frac{dn_A}{dt} = -\frac{1}{3} \frac{dn_B}{dt} = -\frac{1}{3/2} \frac{dn_C}{dt}$ $-\frac{1}{2} \frac{dn_A}{dt} = -\frac{1}{3} \frac{dn_B}{dt} = -\frac{2}{3} \frac{dn_C}{dt}$ Multiplying by $-2$: $\frac{dn_A}{dt} = \frac{2}{3} \frac{dn_B}{dt} = \frac{4}{3} \frac{dn_C}{dt}$

For the reaction $2 A + 3 B + \frac{3}{2} C \rightarrow 3 P$,which statement is correct?

Similar Questions

The average rate of reaction $2SO_{2(g)} + O_{2(g)} \rightarrow 2SO_{3(g)}$ is written as

What is the rate of disappearance of $B$ in the following reaction? $2A + B \rightarrow 3C$,if the rate of appearance of $C$ is $1.3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$.

Ammonia and oxygen react at high temperature as in the reaction,$4 NH_{3(g)} + 5 O_{2(g)} \rightarrow 4 NO_{(g)} + 6 H_2O_{(g)}$. If the rate of formation of $NO$ is $3.6 \times 10^{-3} \ mol \ L^{-1} \ sec^{-1}$,calculate the rate of formation of water.

Why does the rate of reaction increase with respect to product?

For the reaction,$3 I^{-} + S_2 O_8^{2-} \rightarrow I_3^{-} + 2 SO_4^{2-}$,at a particular time $t$,$\frac{d[SO_4^{2-}]}{dt}$ is $2.2 \times 10^{-2} \ mol \ dm^{-3} \ s^{-1}$. What is the value of $-\frac{d[I^{-}]}{dt}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module