For the reaction,

$2{N_2}{O_5}\, \to \,4N{O_2}\, + \,{O_2}$

the rate of reaction is

  • [AIIMS 2006]
  • A

    $\frac{1}{2}\frac{d}{{dt}}[{N_2}{O_5}]$

  • B

    ${2}\frac{d}{{dt}}[{N_2}{O_5}]$

  • C

    $\frac{1}{4}\frac{d}{{dt}}[{N}{O_2}]$

  • D

    $4\frac{d}{{dt}}[N{O_{\,2}}]$

Similar Questions

The rate constant for the reaction $2N_2O_5 \to  4NO_2 + O_2$ is $3.0\times10^{-5}\, sec^{-1}$. If rate is $2.40\times10^{-5}\, M\, sec^{-1}$, then the concentration of $N_2O_5$ (in $M$) is ?

Calculate the overall order of a reaction which has the rate expression

$(a)$ Rate $=k[ A ]^{1 / 2}[ B ]^{3 / 2}$

$(b)$ Rate $=k[ A ]^{3 / 2}[ B ]^{-1}$

Write differential rate expression of following reaction and give its order of reaction:

$CHCl _{3}+ Cl _{2} \rightarrow CCl _{4}+ HCl$

$CH _{3} COOC _{2} H _{5}+ H _{2} O \rightarrow CH _{3} COOH + C_2H_5OH$

Half life of a reaction is found to be inversely proportional to the cube of its initial concentration. The order of reaction is

Consider the following data for the given reaction  $2 \mathrm{HI}_{(\mathrm{g})} \rightarrow \mathrm{H}_{2(\mathrm{~g})}+\mathrm{I}_{2(\mathrm{~g})}$ .  The order of the reaction is................

  $1$ $2$ $3$
$\mathrm{HI}\left(\mathrm{mol} \mathrm{L}^{-1}\right)$ $0.005$ $0.01$ $0.02$
Rate $\left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}-1\right)$ $7.5 \times 10^{-4}$ $3.0 \times 10^{-3}$ $1.2 \times 10^{-2}$

  • [JEE MAIN 2024]