For the reaction,2A + B rightarrow 3C + D, wh | vedclass

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Question

(B) For the reaction $2A + B \rightarrow 3C + D,$ the rate of reaction is expressed as:Rate $= -\frac{1}{2} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac

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$-\frac{d[C]}{3dt}$

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(B) For the reaction $2A + B \rightarrow 3C + D,$ the rate of reaction is expressed as:Rate $= -\frac{1}{2} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3} \frac{d[C]}{dt} = \frac{d[D]}{dt}$Comparing this with the given options:Option $A$ is $-\frac{1}{2} \frac{d[A]}{dt}$ (Correct expression).Option $B$ is $-\frac{d[C]}{3dt}$,but the correct expression for $C$ is $+\frac{1}{3} \frac{d[C]}{dt}$. Thus,this is incorrect.Option $C$ is $-\frac{d[B]}{dt}$ (Correct expression).Option $D$ is $\frac{d[D]}{dt}$ (Correct expression).Therefore,the expression that does not represent the reaction rate is $-\frac{d[C]}{3dt}$.

For the reaction,$2A + B \rightarrow 3C + D,$ which of the following does not express the reaction rate?

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