For the reaction,A to nB. At the point of int | vedclass

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Question

(C) For the reaction $A 	o nB$:At $t=0$,$[A] = A_0$ and $[B] = 0$.At time $t$,let the amount of $A$ reacted be $x$.Then,$[A] = A_0 - x$ and $[B] = nx

Vedclass · Accepted Answer

$\frac{nA_0}{n+1}$

Vedclass · Answer

(C) For the reaction $A 	o nB$:At $t=0$,$[A] = A_0$ and $[B] = 0$.At time $t$,let the amount of $A$ reacted be $x$.Then,$[A] = A_0 - x$ and $[B] = nx$.At the point of intersection,the concentration of $A$ equals the concentration of $B$:$A_0 - x = nx$$A_0 = x(n + 1)$$x = \frac{A_0}{n+1}$Therefore,the concentration of $B$ is:$[B] = nx = n \left(\frac{A_0}{n+1}ight) = \frac{nA_0}{n+1}$

For the reaction,$A \to nB$. At the point of intersection of the two curves in the given graph,the concentration of $B$ is given by:

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