For the propagation of 10 MHz signals as sky | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The critical frequency $f_c$ is related to the maximum electron density $N_{max}$ by the formula: $f_c = 9 \sqrt{N_{max}}$.Squaring both sides,we

Vedclass · Accepted Answer

$ \sim 1.2 	imes 10^{12} \ m^{-3}$

Vedclass · Answer

(A) The critical frequency $f_c$ is related to the maximum electron density $N_{max}$ by the formula: $f_c = 9 \sqrt{N_{max}}$.Squaring both sides,we get $f_c^2 = 81 	imes N_{max}$.Therefore,$N_{max} = \frac{f_c^2}{81}$.Given $f_c = 10 \ MHz = 10 	imes 10^6 \ Hz = 10^7 \ Hz$.Substituting the value: $N_{max} = \frac{(10^7)^2}{81} = \frac{10^{14}}{81} \approx 1.23 	imes 10^{12} \ m^{-3}$.

For the propagation of $10 \ MHz$ signals as sky waves,what should be the minimum electron density in the ionosphere?

Similar Questions

$AM$ is used for broadcasting because...

In amplitude modulation:

In radio broadcasting,the transmission of sound waves is of the type.............

The maximum distance between the transmitting and receiving $TV$ towers is $65 \,km$. If the ratio of the heights of the $TV$ transmitting tower to receiving tower is $36: 49$, the heights of the transmitting and receiving towers respectively are (radius of earth $= 6400 \,km$)

If the area covered by an $FM$ radio station is to be doubled,by what factor must the height of the antenna be increased?

Vedclass Test Series

Exam Paper Generator

Online Exam Module