For the formation of which compound in the El | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Ellingham diagram,the slope of the line for the formation of $CO$ is negative because the reaction $2C(s) + O_2(g) \rightarrow 2CO(g)$ invo

Vedclass · Accepted Answer

$CO$

Vedclass · Answer

(A) In the Ellingham diagram,the slope of the line for the formation of $CO$ is negative because the reaction $2C(s) + O_2(g) \rightarrow 2CO(g)$ involves an increase in the number of moles of gas $(\Delta n_g = 2 - 1 = 1)$.According to the equation $\Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ}$,since $\Delta S^{\circ}$ is positive,the term $-T\Delta S^{\circ}$ becomes more negative as temperature $(T)$ increases.Therefore,the formation of $CO$ becomes more thermodynamically stable and favorable at higher temperatures compared to metal oxides like $FeO$,$ZnO$,or $Cu_2O$,which show positive slopes.

For the formation of which compound in the Ellingham diagram does $\Delta G^{\circ}$ become more and more negative with an increase in temperature?

Similar Questions

Which of the following is not a basic flux?

On heating a mixture of $Cu_2O$ and $Cu_2S$,the product obtained is:

In the extraction of iron using a blast furnace,to remove the impurity $(X)$,chemical $(Y)$ is added to the ore. $X$ and $Y$ are respectively

In metallurgy,flux is a substance used to convert

Cryolite $(Na_3AlF_6)$ helps in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module