For the following data,draw a frequency polygon:
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $1$ $4$ $5$ $10$ $5$ $4$ $1$

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(N/A) To draw a frequency polygon,we first calculate the class marks (mid-values) for each class interval.
Class Mid-value Frequency
$10-20$ $15$ $1$
$20-30$ $25$ $4$
$30-40$ $35$ $5$
$40-50$ $45$ $10$
$50-60$ $55$ $5$
$60-70$ $65$ $4$
$70-80$ $75$ $1$

To close the polygon,we include two imaginary classes: $0-10$ with mid-value $5$ and frequency $0$,and $80-90$ with mid-value $85$ and frequency $0$. Plot these points $(5, 0), (15, 1), (25, 4), (35, 5), (45, 10), (55, 5), (65, 4), (75, 1), (85, 0)$ on a graph and join them with line segments.

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Similar Questions

The information regarding the marks scored by $30$ students in a $50$ marks test is given below:
Marks $(x_{i})$ $15$ $22$ $28$ $31$ $35$ $40$ $44$ $46$
Number of students $(f_{i})$ $2$ $3$ $5$ $6$ $6$ $4$ $3$ $1$

Find the mean of the data.

In a frequency distribution,the mid value of a class is $10$ and the width of the class is $6$. The lower limit of the class is:

Obtain the mean of the following distribution:
Frequency $(f_i)$ Variable $(x_i)$
$4$ $4$
$8$ $6$
$14$ $8$
$11$ $10$
$3$ $12$

The frequency distribution is given below:
Marks$0-20$$20-40$$40-60$$60-100$
Number of Students$10$$15$$20$$25$

This distribution has been represented graphically as shown in the image. Is this representation correct? Explain.

The mean of the following distribution is $50$. Find the value of $a$ and hence the frequencies of $30$ and $70$.
$x$$f$
$10$$17$
$30$$5a+3$
$50$$32$
$70$$7a-11$
$90$$19$

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