(B) For a first order reaction,the number of half-lives $(n)$ in $60 \ \text{min}$ is $n = \frac{t}{t_{1/2}} = \frac{60}{10} = 6$. The remaining fract

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(B) For a first order reaction,the number of half-lives $(n)$ in $60 \ \text{min}$ is $n = \frac{t}{t_{1/2}} = \frac{60}{10} = 6$. The remaining fraction of reactant is given by $\frac{[A]_t}{[A]_0} = (\frac{1}{2})^n = (\frac{1}{2})^6 = \frac{1}{64}$. The fraction of reactant degraded $(x)$ is $1 - \text{remaining fraction} = 1 - \frac{1}{64} = \frac{63}{64}$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Medium

For the first order reaction $A \to \text{Product}$ $(t_{1/2} = 10 \ \text{min})$,the fraction of reactant degraded after an hour from the reaction has started is

A
$\frac{1}{64}$
B
$\frac{63}{64}$
C
$\frac{1}{32}$
D
$\frac{31}{32}$

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Chemical Kinetics

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First Order reaction

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$A$ first order reaction has the rate constant $10^{-2} \ sec^{-1}$. If the initial concentration of reactant is $1 \ M$,then what will be the rate of reaction after $1 \ minute$?

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The half-life of a first-order reaction is

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For the first order reaction $A \to \text{Product}$ $(t_{1/2} = 10 \ \text{min})$,the fraction of reactant degraded after an hour from the reaction has started is

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