For the finite A.P. 85, 80, 75, ldots, -30, f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To

Vedclass · Accepted Answer

$-10$

Vedclass · Answer

(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To find the $n^{th}$ term from the end of an $A.P.$,the formula is $l - (n - 1)d$.Here,we need the $5^{th}$ term from the end,so $n = 5$.$5^{th} 	ext{ term from the end} = l - (5 - 1)d$$= -30 - (4)(-5)$$= -30 + 20$$= -10$.

For the finite $A.P.$ $85, 80, 75, \ldots, -30,$ find the $5^{th}$ term from the end.

Similar Questions

The tenth term of the $A.P.$ with first term $a$ and common difference $d$ is.....

In an $AP$,if $a = 3.5, d = 0, n = 101$,then $a_{n}$ will be

Which term of the $A.P.$ $5, 10, 15, \ldots$ exceeds its $31^{st}$ term by $130$ (in $^{th}$)?

For the finite $A.P.$ $3, 8, 13, \ldots, 253,$ find the $20^{th}$ term from the end.

Which term of the $AP: 21, 42, 63, 84, \ldots$ is $210$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module