For the estimation of nitrogen,1.4 g of an o | vedclass

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(B) The formula for the percentage of nitrogen is: $\% \ N = \frac{1.4 	imes 	ext{meq. of acid consumed}}{	ext{mass of organic compound}}$Step $1$:

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$10$

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(B) The formula for the percentage of nitrogen is: $\% \ N = \frac{1.4 	imes 	ext{meq. of acid consumed}}{	ext{mass of organic compound}}$Step $1$: Calculate milliequivalents $(meq)$ of $H_2SO_4$ taken:$meq 	ext{ of } H_2SO_4 = 60 \ mL 	imes \frac{1}{10} \ M 	imes 2 	ext{ (basicity)} = 12 \ meq$Step $2$: Calculate $meq$ of $NaOH$ used for back titration:$meq 	ext{ of } NaOH = 20 \ mL 	imes \frac{1}{10} \ M 	imes 1 	ext{ (acidity)} = 2 \ meq$Step $3$: Calculate $meq$ of acid consumed by ammonia:$meq 	ext{ of acid consumed} = 12 - 2 = 10 \ meq$Step $4$: Calculate percentage of nitrogen:$\% \ N = \frac{1.4 	imes 10}{1.4} = 10 \%$

Column-$I$	Column-$II$
$(i).$ Magnesium pyrophosphate	$(a).$ $I_2O_5$
$(ii).$ Barium sulphate	$(b).$ $AgX$
$(iii).$ Iodide pentoxide	$(c).$ $Mg_2P_2O_7$
$(iv).$ Silver halide	$(d).$ $BaSO_4$

Similar Questions

The transformation occurring in Dumas's method is given below:
$C_{2}H_{7}N + (2x + \frac{y}{2})CuO \rightarrow xCO_{2} + \frac{y}{2}H_{2}O + \frac{z}{2}N_{2} + (2x + \frac{y}{2})Cu$
The value of $y$ is ...... .(Integer answer)

Match Column-$I$ and Column-$II$ with the correct relation:

Column-$I$ Column-$II$

$(i).$ Magnesium pyrophosphate $(a).$ $I_2O_5$

$(ii).$ Barium sulphate $(b).$ $AgX$

$(iii).$ Iodide pentoxide $(c).$ $Mg_2P_2O_7$

$(iv).$ Silver halide $(d).$ $BaSO_4$

In the $Dumas$ method,the nitrogen-containing organic compound is first heated with which of the following?

Which of the following substances cannot be analyzed using the Kjeldahl method for the estimation of nitrogen?

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