For the combination of logic gates shown in t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The circuit consists of two $OR$ gates whose outputs are fed into a $NAND$ gate. Let the inputs be $A$ and $B$. The output of both $OR$ gates is $

Vedclass · Accepted Answer

$NOR$

Vedclass · Answer

(D) The circuit consists of two $OR$ gates whose outputs are fed into a $NAND$ gate. Let the inputs be $A$ and $B$. The output of both $OR$ gates is $X = A + B$. These are the inputs to the $NAND$ gate. The final output $Y$ is given by $Y = \overline{X \cdot X} = \overline{X} = \overline{A + B}$. This is the Boolean expression for a $NOR$ gate. The truth table is as follows:$A$$B$$X = A + B$$Y = \overline{X \cdot X}$$0$$0$$0$$1$$0$$1$$1$$0$$1$$0$$1$$0$$1$$1$$1$$0$

For the combination of logic gates shown in the figure,the equivalent logic gate is

Similar Questions

The truth table given below corresponds to which logic gate?

$A$ $B$ $X$

$0$ $0$ $0$

$0$ $1$ $1$

$1$ $0$ $1$

$1$ $1$ $1$

Draw the output signals $C_1$ and $C_2$ for the given combination of gates as shown in the figure.

In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?

Which of the following is the correct truth table for the logic gate circuit shown in the figure?

The resultant logic gate from the combination of the following gates is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module