For the chemical reaction $N_{2(g)} + 3 H_{2(g)} \rightleftharpoons 2 NH_{3(g)}$,the correct option is
- A$-\frac{1}{3} \frac{d[H_{2}]}{dt} = -\frac{1}{2} \frac{d[NH_{3}]}{dt}$
- B$-\frac{d[N_{2}]}{dt} = 2 \frac{d[NH_{3}]}{dt}$
- C$-\frac{d[N_{2}]}{dt} = \frac{1}{2} \frac{d[NH_{3}]}{dt}$
- D$3 \frac{d[H_{2}]}{dt} = 2 \frac{d[NH_{3}]}{dt}$
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