For Freundlich adsorption isotherm,a graph of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Freundlich adsorption isotherm equation is given by $\frac{x}{m} = k p^{1/n}$.Taking logarithm on both sides,we get $\log (x / m) = \log k + \

Vedclass · Accepted Answer

$\frac{1}{n}, \log k$

Vedclass · Answer

(B) The Freundlich adsorption isotherm equation is given by $\frac{x}{m} = k p^{1/n}$.Taking logarithm on both sides,we get $\log (x / m) = \log k + \frac{1}{n} \log p$.Comparing this with the equation of a straight line,$y = mx + c$,where $y = \log (x / m)$,$x = \log p$,$m = \frac{1}{n}$,and $c = \log k$.Thus,the slope of the line is $\frac{1}{n}$ and the $Y$-axis intercept is $\log k$.

For Freundlich adsorption isotherm,a graph of $\log (x / m)$ vs $\log (p)$ gives a straight line. The slope of the line and its $Y$-axis intercept respectively are

Similar Questions

The Freundlich adsorption isotherm varies with temperature according to the figure given below. Choose the correct option accordingly.

Which of the following statements is not correct?

Which of the following is $NOT$ a characteristic of chemisorption?

Identify physisorption from the following.

The equation for Freundlich adsorption isotherm is

Vedclass Test Series

Exam Paper Generator

Online Exam Module