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(C) For a distinct and sharp interference pattern,the contrast between the maxima and minima should be maximum.The visibility of the interference frin

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$1 : 1$

Vedclass · Answer

(C) For a distinct and sharp interference pattern,the contrast between the maxima and minima should be maximum.The visibility of the interference fringes is given by $V = \frac{I_{max} - I_{min}}{I_{max} + I_{min}}$.For the best contrast,we require $I_{min} = 0$.Since $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2$,setting $I_{min} = 0$ implies $\sqrt{I_1} = \sqrt{I_2}$,which means $I_1 = I_2$.Therefore,the ratio of the intensities of the two sources must be $1 : 1$.

For a distinct interference pattern to be observed,the necessary condition is that the ratio of the intensity of light emission by both sources should be

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