For any A.P.,T_{25} - T_{20} = ldots ldots ld | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $n^{th}$ term of an $A.P.$ is given by the formula $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{2

Vedclass · Accepted Answer

$5d$

Vedclass · Answer

(A) The $n^{th}$ term of an $A.P.$ is given by the formula $T_n = a + (n - 1)d$,where $a$ is the first term and $d$ is the common difference.For $T_{25}$,we have $T_{25} = a + (25 - 1)d = a + 24d$.For $T_{20}$,we have $T_{20} = a + (20 - 1)d = a + 19d$.Now,calculating the difference: $T_{25} - T_{20} = (a + 24d) - (a + 19d)$.$T_{25} - T_{20} = a + 24d - a - 19d = 5d$.Therefore,the correct option is $A$.

For any $A.P.$,$T_{25} - T_{20} = \ldots \ldots \ldots$

Similar Questions

Yasmeen saves $Rs.\, 32$ during the first month,$Rs.\, 36$ in the second month,and $Rs.\, 40$ in the third month. If she continues to save in this manner,in how many months will she save $Rs.\, 2000$?

Find the $20^{\text{th}}$ term of the $AP$ whose $7^{\text{th}}$ term is $24$ less than the $11^{\text{th}}$ term,first term being $12$.

Which term of the $A.P.$ $5 \frac{1}{2}, 11, 16 \frac{1}{2}, \ldots$ is $550$ (in $^{th}$)?

The measures of all the four angles of a quadrilateral form an $A.P.$. If the common difference is $10^{\circ}$,find the measures of all the angles.

In an $AP$,if $S_{n} = n(4n + 1)$,find the $AP$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module