(B) The modulation index $m$ for an amplitude modulated wave is given by the formula:$m = \frac{A_{\max} - A_{\min}}{A_{\max} + A_{\min}}$Given $m = 0

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(B) The modulation index $m$ for an amplitude modulated wave is given by the formula:$m = \frac{A_{\max} - A_{\min}}{A_{\max} + A_{\min}}$Given $m = 0.5$ and $A_{\max} = 10.0 \ V$.Substituting the values into the formula:$0.5 = \frac{10 - A_{\min}}{10 + A_{\min}}$$0.5(10 + A_{\min}) = 10 - A_{\min}$$5 + 0.5 A_{\min} = 10 - A_{\min}$$1.5 A_{\min} = 5$$A_{\min} = \frac{5}{1.5} = \frac{50}{15} = 3.33 \ V$.

Class 12 Physics Communication Communication

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For an amplitude modulated wave,the modulation index is found to be $0.5$. If the maximum amplitude is found to be $10.0 \ V$,then the minimum amplitude is: (in $V$)

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A
$5.0$
B
$3.33$
C
$2.5$
D
$6.66$

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For an amplitude modulated wave,the modulation index is found to be $0.5$. If the maximum amplitude is found to be $10.0 \ V$,then the minimum amplitude is: (in $V$)

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The height of a $T.V.$ tower is $100 \ m$. What is the population covered by the $T.V.$ broadcast if the average population density around the tower is $1000 \ \text{people}/km^2$?

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