(C) Given,$V_{\max} = 12 \,V$ and $V_{\min} = 3 \,V$. The modulation index $\mu$ is defined as: $\mu = \frac{V_{\max} - V_{\min}}{V_{\max} + V_{\min}}

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(C) Given,$V_{\max} = 12 \,V$ and $V_{\min} = 3 \,V$. The modulation index $\mu$ is defined as: $\mu = \frac{V_{\max} - V_{\min}}{V_{\max} + V_{\min}}$ Substituting the given values: $\mu = \frac{12 - 3}{12 + 3} = \frac{9}{15} = 0.6$ Thus,the modulation index is $0.6$.

Class 12 Physics Communication Communication

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For an amplitude modulated wave,the maximum and minimum amplitudes are $12 \,V$ and $3 \,V$ respectively. Then the modulation index is

AP EAMCET 2023 All AP EAMCET

A
$0.4$
B
$0.9$
C
$0.6$
D
$0.3$

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For an amplitude modulated wave,the maximum and minimum amplitudes are $12 \,V$ and $3 \,V$ respectively. Then the modulation index is

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