For an $AC$ circuit,the potential difference and current are given by $V = 10 \sqrt{2} \sin \omega t$ (in $V$) and $I = 2 \sqrt{2} \cos \omega t$ (in $A$) respectively. The power dissipated in the instrument is ............ $W$.

  • A
    $20$
  • B
    $40$
  • C
    $40 \sqrt{2}$
  • D
    $0$

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