For an $A.P.$,the $7^{th}$ term is $-1$ and the $16^{th}$ term is $17$. Find the general term of the $A.P.$

  • A
    $T_n = 2n - 15$
  • B
    $T_n = 2n - 13$
  • C
    $T_n = 3n - 15$
  • D
    $T_n = 3n - 13$

Explore More

Similar Questions

Yasmeen saves $Rs.\, 32$ during the first month,$Rs.\, 36$ in the second month,and $Rs.\, 40$ in the third month. If she continues to save in this manner,in how many months will she save $Rs.\, 2000$?

Difficult
View Solution

Match the $APs$ given in column $A$ with suitable common differences given in column $B$.
Column $A$ Column $B$
$(A_{1}) \quad 2, -2, -6, -10, \ldots$ $(B_{1}) \quad \frac{2}{3}$
$(A_{2}) \quad a = -18, n = 10, a_{n} = 0$ $(B_{2}) \quad -5$
$(A_{3}) \quad a = 0, a_{10} = 6$ $(B_{3}) \quad 4$
$(A_{4}) \quad a_{2} = 13, a_{4} = 3$ $(B_{4}) \quad -4$
$(B_{5}) \quad 2$
$(B_{6}) \quad \frac{1}{2}$
$(B_{7}) \quad 5$

Difficult
View Solution

The sum of the $5^{\text{th}}$ and the $7^{\text{th}}$ terms of an $AP$ is $52$ and the $10^{\text{th}}$ term is $46$. Find the $AP$.

Difficult
View Solution

The $8^{th}$ term of an $A.P.$ is $31$ and its $15^{th}$ term exceeds its $11^{th}$ term by $16$. Find the $A.P.$ and also its $20^{th}$ term.

The first term of a finite $A.P.$ is $5$ and its last term is $45$. If the sum of all the terms is $500$,there are $\ldots$ terms in the $A.P.$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo