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(A) The velocity of light in a medium is given by the formula $v = \frac{1}{\sqrt{\mu \epsilon}}$.Substituting $\mu = \mu_{r} \mu_{0}$ and $\epsilon =

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$2.5 	imes 10^{8} \;m/s$

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(A) The velocity of light in a medium is given by the formula $v = \frac{1}{\sqrt{\mu \epsilon}}$.Substituting $\mu = \mu_{r} \mu_{0}$ and $\epsilon = \epsilon_{r} \epsilon_{0}$,we get $v = \frac{1}{\sqrt{\mu_{r} \epsilon_{r} \mu_{0} \epsilon_{0}}}$.Since the speed of light in vacuum is $c = \frac{1}{\sqrt{\mu_{0} \epsilon_{0}}} = 3 	imes 10^{8} \;m/s$,the formula becomes $v = \frac{c}{\sqrt{\mu_{r} \epsilon_{r}}}$.Given $\mu_{r} = 1.0$ and $\epsilon_{r} = 1.44$,we have $v = \frac{3 	imes 10^{8}}{\sqrt{1.0 	imes 1.44}}$.$v = \frac{3 	imes 10^{8}}{\sqrt{1.44}} = \frac{3 	imes 10^{8}}{1.2}$.$v = 2.5 	imes 10^{8} \;m/s$.

For a transparent medium,the relative permeability $\mu_{r}$ and relative permittivity $\epsilon_{r}$ are $1.0$ and $1.44$ respectively. The velocity of light in this medium would be,

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