For a transistor,the parameter $\beta = 99$. The value of the parameter $\alpha$ is

In the study of a transistor as an amplifier,the ratio of collector current to emitter current is $0.98$. Then,the ratio of collector current to base current will be:

In a common base amplifier,the phase difference between the input signal voltage and the output voltage is

The current gain of a transistor in common emitter configuration is $80$. The resistances in collector and base sides of the circuit are $5 \text{ k}\Omega$ and $1 \text{ k}\Omega$ respectively. If the input voltage is $2 \text{ mV}$, the output voltage is: (in $\text{ V}$)

The dc common emitter current gain of an $n-p-n$ transistor is $50$. The potential difference applied across the collector and emitter of a transistor used in $CE$ configuration is $V_{CE} = 2 \ V$. If the collector resistance $R_{C} = 4 \ k\Omega$,the base current $(I_{B})$ and the collector current $(I_{C})$ are:

The collector current in a common base amplifier using $n-p-n$ transistor is $24\; mA$. If $80\%$ of the electrons released by the emitter are accepted by the collector,then the base current is numerically