For a thermocouple,the neutral temperature is | vedclass

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(C) In a thermocouple,the neutral temperature $	heta_n$ is the arithmetic mean of the cold junction temperature $	heta_c$ and the inversion temperat

Vedclass · Accepted Answer

$520$

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(C) In a thermocouple,the neutral temperature $	heta_n$ is the arithmetic mean of the cold junction temperature $	heta_c$ and the inversion temperature $	heta_i$. The relation is given by: $	heta_n = \frac{	heta_i + 	heta_c}{2}$.Given that there is no deflection in the galvanometer,the hot junction temperature is at the inversion temperature $	heta_i$.Given: $	heta_n = 270\,^\circ C$ and $	heta_c = 20\,^\circ C$.Substituting these values into the formula: $270 = \frac{	heta_i + 20}{2}$.$540 = 	heta_i + 20$.$	heta_i = 540 - 20 = 520\,^\circ C$.

For a thermocouple,the neutral temperature is $270\,^\circ C$ and the temperature of its cold junction is $20\,^\circ C$. If there is no deflection in the galvanometer,the temperature of the hot junction should be .............. $^\circ C$

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