For a small angled prism with prism angle A,t | vedclass

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(C) For a small angled prism,the angle of minimum deviation is given by $\delta = (\mu - 1)A$.This equation can be rewritten as $\delta = A\mu - A$.Co

Vedclass · Accepted Answer

Slope $= A$

Vedclass · Answer

(C) For a small angled prism,the angle of minimum deviation is given by $\delta = (\mu - 1)A$.This equation can be rewritten as $\delta = A\mu - A$.Comparing this with the equation of a straight line $y = mx + c$,where $y = \delta$ and $x = \mu$:$1$. The slope $m = A$.$2$. The intercept $c = -A$.At point $P$,the deviation $\delta = 0$. Substituting this into the equation: $0 = (\mu - 1)A$. Since $A 
eq 0$,we get $\mu - 1 = 0$,which means $\mu = 1$. Thus,point $P$ corresponds to $\mu = 1$.Since the slope is $A$,option $C$ is correct.

For a small angled prism with prism angle $A$,the angle of minimum deviation $\delta$ varies with the refractive index $\mu$ of the prism as shown in the graph.

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