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(D) The rate law expression is given by $	ext{Rate} = k[A]^\alpha[B]^\beta$.From entry $1$ and $2$,$[A]$ is constant. Taking the ratio:$\frac{4 	ime

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$50$

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(D) The rate law expression is given by $	ext{Rate} = k[A]^\alpha[B]^\beta$.From entry $1$ and $2$,$[A]$ is constant. Taking the ratio:$\frac{4 	imes 10^{-2}}{2 	imes 10^{-2}} = \frac{k[0.02]^\alpha[0.04]^\beta}{k[0.02]^\alpha[0.02]^\beta}$$2 = [2]^\beta \Rightarrow \beta = 1$.From entry $2$ and $3$,$[B]$ is constant. Taking the ratio:$\frac{8 	imes 10^{-2}}{4 	imes 10^{-2}} = \frac{k[0.04]^\alpha[0.04]^\beta}{k[0.02]^\alpha[0.04]^\beta}$$2 = [2]^\alpha \Rightarrow \alpha = 1$.Substituting $\alpha = 1$ and $\beta = 1$ into entry $1$:$2 	imes 10^{-2} = k[0.02]^1[0.02]^1$$k = \frac{2 	imes 10^{-2}}{4 	imes 10^{-4}} = \frac{200}{4} = 50 	ext{ } M^{-1}s^{-1}$.

Entry	$[A]$ in $M$	$[B]$ in $M$	Initial rate $(M/s)$
$1$	$0.02$	$0.02$	$2 \times 10^{-2}$
$2$	$0.02$	$0.04$	$4 \times 10^{-2}$
$3$	$0.04$	$0.04$	$8 \times 10^{-2}$

$P_0 \text{ (mmHg)}$	$250$	$300$
$t_{1/2} \text{ (minutes)}$	$135$	$112.5$

$[CH_3COCH_3]$	$[Br_2]$	$[H^+]$
$0.30$	$0.05$	$0.05$
$0.30$	$0.10$	$0.05$
$0.30$	$0.10$	$0.10$
$0.40$	$0.05$	$0.20$

For a reaction $A + B \longrightarrow P$,the following data are provided. The rate constant for this reaction in standard units is:
Entry $[A]$ in $M$ $[B]$ in $M$ Initial rate $(M/s)$
$1$ $0.02$ $0.02$ $2 \times 10^{-2}$
$2$ $0.02$ $0.04$ $4 \times 10^{-2}$
$3$ $0.04$ $0.04$ $8 \times 10^{-2}$

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For a reaction $A + B \longrightarrow P$,the following data are provided. The rate constant for this reaction in standard units is:Entry$[A]$ in $M$$[B]$ in $M$Initial rate $(M/s)$$1$$0.02$$0.02$$2 \times 10^{-2}$$2$$0.02$$0.04$$4 \times 10^{-2}$$3$$0.04$$0.04$$8 \times 10^{-2}$