For a particular resonance tube,following are four of the six harmonics below $1000 \,Hz$: $300, 600, 750$ and $900 \,Hz$. The two missing harmonics are:

The second overtone of an open organ pipe is equal to the first overtone of a closed organ pipe. If the length of the closed organ pipe is $15 \ cm$,the length of the open organ pipe is: (in $cm$)

The fundamental frequency of a closed pipe is equal to the frequency of the second harmonic of an open pipe. The ratio of their lengths is

The second overtone of an open organ pipe $A$ and a closed pipe $B$ have the same frequency at a given temperature. It follows that the ratio of the

The frequency of the fundamental tone in an open organ pipe of length $0.48 \ m$ is $320 \ Hz$. The speed of sound is $320 \ m/s$. What will be the frequency of the fundamental tone in a closed organ pipe of the same length?

An open organ pipe of length $l$ is sounded together with another organ pipe of length $l + x$ in their fundamental tones $(x << l)$. The beat frequency heard will be (speed of sound is $v$):