For a particle performing S.H.M.,which of the | vedclass

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(D) In $S.H.M.$,the displacement is given by $x = A \sin(\omega t + \phi)$.Velocity is given by $v = \frac{dx}{dt} = A\omega \cos(\omega t + \phi)$. A

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The velocity of the particle is minimum at the mean position.

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(D) In $S.H.M.$,the displacement is given by $x = A \sin(\omega t + \phi)$.Velocity is given by $v = \frac{dx}{dt} = A\omega \cos(\omega t + \phi)$. At the mean position $(x = 0)$,the velocity is maximum $(v_{max} = A\omega)$.Acceleration is given by $a = -\omega^2 x$. At the mean position $(x = 0)$,acceleration is minimum $(a = 0)$.The restoring force $F = -kx$ is always directed towards the mean position.The total energy $E = K.E. + P.E. = \frac{1}{2}kA^2$ remains constant at all times.Therefore,statement $D$ is incorrect because the velocity is maximum,not minimum,at the mean position.

For a particle performing $S.H.M.$,which of the following statements is $INCORRECT$?

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