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(C) For a monoatomic gas at constant pressure,the work done is given by $W = p \Delta V$.Using the ideal gas equation $pV = nRT$,we have $W = nR \Delt

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$\frac{3}{2} W$

Vedclass · Answer

(C) For a monoatomic gas at constant pressure,the work done is given by $W = p \Delta V$.Using the ideal gas equation $pV = nRT$,we have $W = nR \Delta T$.At constant volume,the heat supplied is equal to the change in internal energy,given by $Q = n C_v \Delta T$.For a monoatomic gas,the molar heat capacity at constant volume is $C_v = \frac{3}{2} R$.Substituting this into the heat equation,we get $Q = n \left( \frac{3}{2} R \right) \Delta T$.Since $W = nR \Delta T$,we can substitute $nR \Delta T$ with $W$.Therefore,$Q = \frac{3}{2} W$.

For a monoatomic gas,the work done at constant pressure is $W$. For the same rise in temperature of the gas,the heat supplied at constant volume is:

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