For a given reaction $3A + B \to C + D$,the rate of reaction can be represented by:

  • A
    $-\frac{1}{3}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{d[C]}{dt} = \frac{d[D]}{dt}$
  • B
    $-\frac{1}{3}\frac{d[A]}{dt} = \frac{d[C]}{dt} = K[A]^m[B]^n$
  • C
    $+\frac{1}{3}\frac{d[A]}{dt} = -\frac{d[C]}{dt} = K[A]^n[B]^m$
  • D
    None of these

Explore More

Similar Questions

For the reaction,$5Br^-{_{\text{(aq)}}} + BrO_3^-{_{\text{(aq)}}} + 6H^+{_{\text{(aq)}}} \rightarrow 3Br_{2\text{(aq)}} + 3H_2O_{\text{(l)}}$,if $-\frac{\Delta[Br^{-}]}{\Delta t} = 0.05 \ mol \ L^{-1} \ min^{-1}$,then the value of $-\frac{\Delta[BrO_3^{-}]}{\Delta t}$ in $mol \ L^{-1} \ min^{-1}$ is:

The reaction given below $2 NH_{3(g)} \xrightarrow{Pt} N_{2(g)} + 3 H_{2(g)}$ has a rate of reaction of $2.5 \times 10^{-6} \ mol \ dm^{-3} \ sec^{-1}$. What is the rate of formation of $H_{2(g)}$?

For the reaction $5 Br_{(aq)}^{-} + BrO_{3_{(aq)}}^{-} + 6 H_{(aq)}^{+} \rightarrow 3 Br_{2_{(aq)}} + 3 H_{2}O_{(l)}$,write the rate of reaction expression.

$A$ gaseous hypothetical chemical equation $2A \rightleftharpoons 4B + C$ is carried out in a closed vessel. The concentration of $B$ is found to increase by $5 \times 10^{-3} \ mol \ L^{-1}$ in $10 \ s$. The rate of appearance of $B$ is

$A \rightarrow B$ is a first order reaction. The concentration of $A$ is decreased from $x \ mol \ L^{-1}$ to $y \ mol \ L^{-1}$ in $100 \ \min$. What is the average velocity of the reaction in $mol \ L^{-1} \ \min^{-1}$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo