For a concave mirror, if a virtual image is f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a concave mirror, the magnification $m$ is given by $m = \frac{f}{f - u}$.When a virtual image is formed, the object distance $u$ lies between

Vedclass · Accepted Answer

Vedclass · Answer

(B) For a concave mirror, the magnification $m$ is given by $m = \frac{f}{f - u}$.When a virtual image is formed, the object distance $u$ lies between $0$ and $f$ (i.e., $0 At $u = 0$, $m = \frac{f}{f - 0} = 1$.As $u$ approaches $f$ from the left $(u 	o f^-)$, the denominator $(f - u)$ approaches $0$ from the positive side, so $m 	o \infty$.Since $m = \frac{f}{f - u}$, we can write $m(f - u) = f$, which implies $mf - mu = f$, or $mu = f(m - 1)$, which gives $u = f(1 - \frac{1}{m})$.This represents a curve where $m$ increases from $1$ to $\infty$ as $u$ increases from $0$ to $f$. This matches the graph shown in option $B$.

For a concave mirror, if a virtual image is formed, the graph between $m$ and $u$ is of the form:

Similar Questions

When seen in green light,the saffron and green portions of our National Flag will appear to be

The object distance $u$,the image distance $v$,and the magnification $m$ in a lens follow certain linear relations. These are:

If the focal length of the objective lens is increased,then:

$Lux$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module