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(B) In a transistor,the current gain parameters are defined as $\beta = \frac{I_C}{I_B}$ and $\alpha = \frac{I_C}{I_E}$.Since $I_E = I_B + I_C$,we can

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$\alpha = \frac{\beta}{1 - \beta}$

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(B) In a transistor,the current gain parameters are defined as $\beta = \frac{I_C}{I_B}$ and $\alpha = \frac{I_C}{I_E}$.Since $I_E = I_B + I_C$,we can write $\alpha = \frac{I_C}{I_B + I_C}$.Dividing the numerator and denominator by $I_C$,we get $\alpha = \frac{1}{\frac{I_B}{I_C} + 1} = \frac{1}{\frac{1}{\beta} + 1} = \frac{\beta}{1 + \beta}$.From this,we can derive $\frac{1}{\alpha} = \frac{1 + \beta}{\beta} = \frac{1}{\beta} + 1$,which implies $\frac{1}{\beta} = \frac{1}{\alpha} - 1$.Comparing these with the given options,the relation $\alpha = \frac{\beta}{1 - \beta}$ is incorrect.

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

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