For a chemical reaction,the rate law is $\text{rate} = k[A]^2[B]$. If $[A]$ is doubled at constant $[B]$,the rate of reaction:

  • A
    Increases by a factor of $8$
  • B
    Increases by a factor of $4$
  • C
    Increases by a factor of $3$
  • D
    Increases by a factor of $2$

Explore More

Similar Questions

What is the order of reaction for the rate law $r = k [A]^{\frac{3}{2}} [B]^2$ ?

What is the order of a reaction which has a rate expression $\text{rate} = K[A]^{3/2}[B]^{-1}$?

The rate law for a reaction between reactants $A$,$B$,and $C$ is $r = K[A][B][C]^2$. If the concentration of $A$ is halved,then the rate of reaction:

For the reaction $2A + B \rightarrow \text{Product}$,the rate constant $(K)$ is $2.5 \times 10^{-5} \text{ L mol}^{-1} \text{ s}^{-1}$ after $15 \text{ s}$,$2.60 \times 10^{-5} \text{ L mol}^{-1} \text{ s}^{-1}$ after $30 \text{ s}$,and $2.55 \times 10^{-5} \text{ L mol}^{-1} \text{ s}^{-1}$ after $50 \text{ s}$. What is the order of the reaction?

The given data are for the reaction:
$2NO_{(g)} + Cl_{2(g)} \to 2NOCl_{(g)}$ at $298 \ K$
Experiment$[Cl_2] \ (M)$$[NO] \ (M)$Rate $(mol \ L^{-1} \sec^{-1})$
$I$$0.05$$0.05$$1 \times 10^{-3}$
$II$$0.15$$0.05$$3 \times 10^{-3}$
$III$$0.05$$0.15$$9 \times 10^{-3}$

The rate law for the reaction is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo