For a cell constructed with Cu and Ag electro | vedclass

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Question

(A) The electrode with the higher standard reduction potential acts as the cathode. Given standard reduction potentials: $E_{Ag^+/Ag}^{\circ} = +0.80

Vedclass · Accepted Answer

Copper electrode acts as anode and $E_{cell}^{\circ}$ is $+0.46 \ V$

Vedclass · Answer

(A) The electrode with the higher standard reduction potential acts as the cathode. Given standard reduction potentials: $E_{Ag^+/Ag}^{\circ} = +0.80 \ V$ and $E_{Cu^{2+}/Cu}^{\circ} = +0.34 \ V$. Since $E_{Ag^+/Ag}^{\circ} > E_{Cu^{2+}/Cu}^{\circ}$,the silver electrode acts as the cathode and the copper electrode acts as the anode. The standard cell potential is calculated as: $E_{cell}^{\circ} = E_{cathode}^{\circ} - E_{anode}^{\circ}$ $E_{cell}^{\circ} = +0.80 \ V - (+0.34 \ V) = +0.46 \ V$.

For a cell constructed with $Cu$ and $Ag$ electrodes,which of the following statements is correct regarding the cathode and the standard cell potential $(E_{cell}^{\circ})$?

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