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(C) The reaction $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ proceeds through an $S_N2$ mechanism.In an $S_N2$ reaction,the rate-determining step in

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rate $= k[CH_3Br][OH^{-}]$

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(C) The reaction $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ proceeds through an $S_N2$ mechanism.In an $S_N2$ reaction,the rate-determining step involves both the substrate and the nucleophile.Therefore,the rate law is given by the expression $rate = k[CH_3Br][OH^{-}]$.This is a second-order reaction where the rate depends on the concentration of both the methyl bromide and the hydroxide ion.

For $CH_3Br + OH^{-} \rightarrow CH_3OH + Br^{-}$ the rate of reaction is given by the expression:

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