(A) For $1$ mol of an ideal gas,the equation is $PV = nRT$. Since $n = 1$,we have $PV = RT$.At the $PV$ axis,the pressure $P$ approaches $0$. For a re

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For $1$ mol of an ideal gas,the equation is $PV = nRT$. Since $n = 1$,we have $PV = RT$.At the $PV$ axis,the pressure $P$ approaches $0$. For a real gas,as $P \to 0$,the gas behaves ideally.Therefore,the intercept on the $PV$ axis is given by $\lim_{P \to 0} PV = nRT$.Given the intercept is $20$,we have $20 = (1) \times R \times T$.Solving for $T$,we get $T = \frac{20}{R}$.

Class 11 Chemistry States of Matter Real gases and Vander waal’s equation

Medium

For $1$ mol of a real gas kept at constant temperature $T$,the graph of $PV$ vs $P$ intersects the $PV$ axis at $20$. Hence,the temperature $T$ is ($R$ = universal gas constant).

A
$\frac{20}{R}$
B
$\frac{2}{R}$
C
$\frac{1}{10R}$
D
$\frac{1}{20R}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Real gases and Vander waal’s equation

What is the actual volume occupied by molecules in $1 \text{ mole}$ of water vapor at $STP$?

Medium

View Solution

At low pressures,van der Waals' equation is written as $(P + \frac{a}{V^2})V = RT$. The compressibility factor $Z$ will be

Medium

View Solution

The compressibility factor for a real gas at high pressure is

Easy

View Solution

Consider the following figure. Which of the following gases show negative as well as positive deviation from the ideal gas behaviour?

Medium

View Solution

In the van der Waals equation of state for a real gas,the term representing intermolecular forces is .......

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For $1$ mol of a real gas kept at constant temperature $T$,the graph of $PV$ vs $P$ intersects the $PV$ axis at $20$. Hence,the temperature $T$ is ($R$ = universal gas constant).

Similar Questions

What is the actual volume occupied by molecules in $1 \text{ mole}$ of water vapor at $STP$?

At low pressures,van der Waals' equation is written as $(P + \frac{a}{V^2})V = RT$. The compressibility factor $Z$ will be

The compressibility factor for a real gas at high pressure is

Consider the following figure. Which of the following gases show negative as well as positive deviation from the ideal gas behaviour?

In the van der Waals equation of state for a real gas,the term representing intermolecular forces is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module