For the reaction $R \to P$,describe the nature of the graphs of $[R]$ versus $time$ and $[P]$ versus $time$.

  • A
    Both graphs are straight lines with positive slopes.
  • B
    Both graphs are straight lines with negative slopes.
  • C
    $[R]$ vs $time$ is a decreasing curve,while $[P]$ vs $time$ is an increasing curve.
  • D
    $[R]$ vs $time$ is an increasing curve,while $[P]$ vs $time$ is a decreasing curve.

Explore More

Similar Questions

$A \rightarrow P$ is a first order reaction. The following graph is obtained for this reaction,($x$-axis $=$ time; $y$-axis $=$ concentration of $A$). The instantaneous rate of the reaction at point $C$ is

The instantaneous rate of a reaction is given by $-\frac{1}{2} \frac{d[x]}{dt} = -\frac{d[y]}{dt} = \frac{1}{2} \frac{d[z]}{dt}$. Identify the reaction.

Observe the following reaction: $2 A + B \longrightarrow C$. The rate of formation of $C$ is $2.2 \times 10^{-3} \ mol \ L^{-1} \ min^{-1}$. What is the value of $-\frac{d[A]}{d t}$ (in $mol \ L^{-1} \ min^{-1}$)?

$A$ gaseous hypothetical chemical equation $2A \rightleftharpoons 4B + C$ is carried out in a closed vessel. The concentration of $B$ is found to increase by $5 \times 10^{-3} \ mol \ L^{-1}$ in $10 \ s$. The rate of appearance of $B$ is

For the reaction $2 N_2O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$,the initial concentration of $N_2O_5$ is $2.0 \ mol \ L^{-1}$ and after $300 \ min$,it is reduced to $1.4 \ mol \ L^{-1}$. The rate of production of $NO_2$ (in $mol \ L^{-1} \ min^{-1}$) is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo