For $H_3PO_3$ and $H_3PO_4$,the correct choice is:
- A$H_3PO_3$ is dibasic and reducing.
- B$H_3PO_3$ is dibasic and non-reducing.
- C$H_3PO_4$ is tribasic and reducing.
- D$H_3PO_3$ is tribasic and non-reducing.
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Similar Questions
Which of the following statements is $NOT$ true for both white and red phosphorus?
Easy
View SolutionMatch List-$I$ with List-$II$
List-$I$ Name of oxo acid List-$II$ Oxidation state of $P$ $(a)$ Hypophosphorous acid $(i) +5$ $(b)$ Orthophosphoric acid $(ii) +4$ $(c)$ Hypophosphoric acid $(iii) +3$ $(d)$ Orthophosphorous acid $(iv) +2$ $(v) +1$
Choose the correct answer from the options given below:
| List-$I$ Name of oxo acid | List-$II$ Oxidation state of $P$ |
| $(a)$ Hypophosphorous acid | $(i) +5$ |
| $(b)$ Orthophosphoric acid | $(ii) +4$ |
| $(c)$ Hypophosphoric acid | $(iii) +3$ |
| $(d)$ Orthophosphorous acid | $(iv) +2$ |
| $(v) +1$ |
Choose the correct answer from the options given below:
The reaction of elemental $P_4$ and aqueous $NaOH$ gives
Difficult
View SolutionNitrogen dioxide cannot be prepared by heating:
Easy
View SolutionAt what temperature is red phosphorus heated to obtain $\alpha$-black phosphorus (in $K$)?
Easy
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