Fluorine is more electronegative than either | vedclass

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(D) The $BF_3$ molecule must be planar triangular. $BF_3$ has a planar triangular geometry where the three $B-F$ bond dipoles cancel each other out du

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The $BF_3$ molecule must be planar triangular.

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(D) The $BF_3$ molecule must be planar triangular. $BF_3$ has a planar triangular geometry where the three $B-F$ bond dipoles cancel each other out due to symmetry,resulting in a net dipole moment of $0$. $PF_3$ has a pyramidal geometry with a lone pair on the phosphorus atom,which prevents the bond dipoles from canceling out,resulting in a non-zero dipole moment.

Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that $BF_3$ has no dipole moment but $PF_3$ does?

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