Five positive charges,each having charge $q$,are placed at the vertices of a regular pentagon as shown in the figure. The electric potential $(V)$ and the electric field $(\vec{E})$ at the center $O$ of the pentagon due to these five positive charges are:

• A
  $V=\frac{5 q}{4 \pi \varepsilon_0 r}$ and $\vec{E}=0$
• B
  $V=\frac{5 q}{4 \pi \varepsilon_0 r}$ and $\vec{E}=\frac{5 \sqrt{3} q}{8 \pi \varepsilon_0 r^2} \hat{r}$
• C
  $V=\frac{5 q}{4 \pi \varepsilon_0 r}$ and $\vec{E}=\frac{5 q}{4 \pi \varepsilon_0 r^2} \hat{r}$
• D
  $V=0$ and $\vec{E}=0$