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(D) Let the third number be $100$.Since the first number is $30 \%$ less than the third number,the first number $= 100 - 30 = 70$.Since the second num

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$10$

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(D) Let the third number be $100$.Since the first number is $30 \%$ less than the third number,the first number $= 100 - 30 = 70$.Since the second number is $37 \%$ less than the third number,the second number $= 100 - 37 = 63$.We need to find how much less the second number is than the first number in terms of percentage.Difference $= 70 - 63 = 7$.Required percentage $= \left( \frac{	ext{Difference}}{	ext{First number}} ight) 	imes 100 = \left( \frac{7}{70} ight) 	imes 100$.$= 0.1 	imes 100 = 10 \%$.

The first and second numbers are less than a third number by $30 \%$ and $37 \%$,respectively. The second number is less than the first by: (in $\%$)

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