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(C) Given equation is $8 x^{2}+2 x-3=0$.On comparing with $a x^{2}+b x+c=0$,we get $a=8, b=2$ and $c=-3$.Discriminant,$D = b^{2}-4 a c = (2)^{2}-4(8)(

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$\frac{1}{2}, -\frac{3}{4}$

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(C) Given equation is $8 x^{2}+2 x-3=0$.On comparing with $a x^{2}+b x+c=0$,we get $a=8, b=2$ and $c=-3$.Discriminant,$D = b^{2}-4 a c = (2)^{2}-4(8)(-3) = 4+96 = 100$.Since $D > 0$,the equation has two distinct real roots.Using the quadratic formula,$x = \frac{-b \pm \sqrt{D}}{2 a}$.$x = \frac{-2 \pm \sqrt{100}}{2(8)} = \frac{-2 \pm 10}{16}$.Case $1$: $x = \frac{-2+10}{16} = \frac{8}{16} = \frac{1}{2}$.Case $2$: $x = \frac{-2-10}{16} = \frac{-12}{16} = -\frac{3}{4}$.Thus,the roots are $\frac{1}{2}$ and $-\frac{3}{4}$.

Find whether the following equation has real roots. If real roots exist,find them.
$8 x^{2}+2 x-3=0$

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Find whether the following equation has real roots. If real roots exist,find them.$8 x^{2}+2 x-3=0$