Find the velocity of the hanging block if the | vedclass

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(A) Let the velocity of the hanging block be $v$ in the upward direction.Using the constraint relation for the pulley system,the sum of the velocities

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$3/2 \, m/s \uparrow$

Vedclass · Answer

(A) Let the velocity of the hanging block be $v$ in the upward direction.Using the constraint relation for the pulley system,the sum of the velocities of the rope segments connected to the movable pulley must be equal to twice the velocity of the pulley.Taking upward as positive,the velocities of the two segments of the rope connected to the movable pulley are $2 \, m/s$ (upward) and $1 \, m/s$ (upward).Therefore,$2v = v_1 + v_2$,where $v_1 = 2 \, m/s$ and $v_2 = 1 \, m/s$.$2v = 2 + 1$$2v = 3$$v = 3/2 \, m/s$ (upward).Thus,the velocity of the hanging block is $3/2 \, m/s$ in the upward direction.

Find the velocity of the hanging block if the velocities of the free ends of the rope are as indicated in the figure.

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