Find the value of T_1 (in N),if the system is | vedclass

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(B) The system is in translational and rotational equilibrium.For translational equilibrium,the sum of upward forces equals the downward force (weight

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$50$

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(B) The system is in translational and rotational equilibrium.For translational equilibrium,the sum of upward forces equals the downward force (weight of the rod):$T_1 + T_2 = mg = 10 \ kg 	imes 10 \ m/s^2 = 100 \ N$  (Equation $1$)For rotational equilibrium,the net torque about any point must be zero. Let us take the torque about the point where $T_2$ is applied:$	au_{	ext{net}} = 0$$T_1 	imes \ell - mg 	imes \frac{\ell}{2} = 0$$T_1 	imes \ell = 100 	imes \frac{\ell}{2}$$T_1 = 50 \ N$

Find the value of $T_1$ (in $N$),if the system is in equilibrium and the mass of the rod is $10 \ kg$ and its length is $10 \ m$. $[g = 10 \ m/s^2]$ (in $N$)

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