Find the sum of the following APs: 0.6, 1.7, | vedclass

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(A) For the given $A.P.$: $0.6, 1.7, 2.8, \ldots,$ to $100$ terms.Here,the first term $a = 0.6$.The common difference $d = a_2 - a_1 = 1.7 - 0.6 = 1.1

Vedclass · Accepted Answer

$5505$

Vedclass · Answer

(A) For the given $A.P.$: $0.6, 1.7, 2.8, \ldots,$ to $100$ terms.Here,the first term $a = 0.6$.The common difference $d = a_2 - a_1 = 1.7 - 0.6 = 1.1$.The number of terms $n = 100$.The sum of $n$ terms of an $A.P.$ is given by the formula:$S_n = \frac{n}{2} [2a + (n - 1)d]$Substituting the values:$S_{100} = \frac{100}{2} [2(0.6) + (100 - 1) 	imes 1.1]$$S_{100} = 50 [1.2 + 99 	imes 1.1]$$S_{100} = 50 [1.2 + 108.9]$$S_{100} = 50 [110.1]$$S_{100} = 5505$Thus,the sum of the first $100$ terms is $5505$.

Find the sum of the following $APs$: $0.6, 1.7, 2.8, \ldots,$ to $100$ terms.

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