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(A) Given quadratic equation: $100 x^{2}-20 x+1=0$To factorise,we split the middle term $-20x$ into $-10x - 10x$:$100 x^{2}-10 x-10 x+1=0$Group the te

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$x = \frac{1}{10}, \frac{1}{10}$

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(A) Given quadratic equation: $100 x^{2}-20 x+1=0$To factorise,we split the middle term $-20x$ into $-10x - 10x$:$100 x^{2}-10 x-10 x+1=0$Group the terms:$10 x(10 x-1)-1(10 x-1)=0$Factor out the common term $(10 x-1)$:$(10 x-1)(10 x-1)=0$$(10 x-1)^{2}=0$For the roots,set the factor to zero:$10 x-1=0$$10 x=1$$x=\frac{1}{10}$Since the factor is squared,the roots are equal: $x = \frac{1}{10}, \frac{1}{10}$.

Find the roots of the following quadratic equation by factorisation:
$100 x^{2}-20 x+1=0$

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Find the roots of the following quadratic equation by factorisation:$100 x^{2}-20 x+1=0$