(C) Given: Edge length of the cube,$l = 60 \text{ cm} = 0.6 \text{ m} = 60 \times 10^{-2} \text{ m}$.Resistivity of the material,$\rho = 60 \times 10^

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(C) Given: Edge length of the cube,$l = 60 \text{ cm} = 0.6 \text{ m} = 60 \times 10^{-2} \text{ m}$.Resistivity of the material,$\rho = 60 \times 10^{-8} \Omega \text{ m}$.The area of cross-section of the cube is $A = l^2 = (60 \times 10^{-2} \text{ m})^2$.The formula for resistance is $R = \frac{\rho l}{A}$.Substituting the values:$R = \frac{60 \times 10^{-8} \times (60 \times 10^{-2})}{(60 \times 10^{-2})^2}$$R = \frac{60 \times 10^{-8}}{60 \times 10^{-2}}$$R = 1 \times 10^{-6} \Omega$.

Class 12 Physics Current Electricity Resistance of wire, Resistivity and Conductivity

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Find the resistance of a cube of edge $60 \text{ cm}$,made of a material of specific resistance $60 \times 10^{-8} \Omega \text{ m}$.

AP EAMCET 2021 All AP EAMCET

A
$2.5 \times 10^{-5} \Omega$
B
$10^{-8} \Omega$
C
$10^{-6} \Omega$
D
$5 \times 10^{-4} \Omega$

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Current Electricity

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Resistance of wire, Resistivity and Conductivity

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Find the resistance of a cube of edge $60 \text{ cm}$,made of a material of specific resistance $60 \times 10^{-8} \Omega \text{ m}$.

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$A$ cylindrical copper rod has length $L$ and resistance $R$. If it is melted and formed into another rod of length $2 L$,then the resistance will be ....... $R$.

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