Find the radius of an atom in $fcc$ unit cell having edge length $393 \ pm$. (in $pm$)

$A$ compound formed by elements $X$ and $Y$ crystallises in a cubic structure,where $X$ atoms are at the corners of a cube and $Y$ atoms are at the body centre. The formula of the compound is:

The unit cell of a binary compound of $A$ and $B$ metals has a $ccp$ structure with $A$ atoms occupying the corners and $B$ atoms occupying the centres of each face of the cubic unit cell. If during the crystallisation of this alloy,two $A$ atoms are missing from the unit cell,the overall composition per unit cell is:

In a face-centered cubic unit cell,what fraction of an atom at the corner is shared by the unit cell?

An ionic compound has a unit cell consisting of $A$ ions at the corners of a cube and $B$ ions on the centres of the faces of the cube. The empirical formula for this compound would be

Calculate the total volume occupied by all atoms in a simple cubic unit cell if the radius of the atom is $3 \times 10^{-8} \ cm$.