Find the number of bricks,each measuring 25, | vedclass

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(A) $1$. Calculate the total volume of the wall in cubic centimeters $(cm^3)$: Wall dimensions are $12\, m 	imes 5\, m 	imes 0.25\, m$. Converting t

Vedclass · Accepted Answer

$6080$

Vedclass · Answer

(A) $1$. Calculate the total volume of the wall in cubic centimeters $(cm^3)$: Wall dimensions are $12\, m 	imes 5\, m 	imes 0.25\, m$. Converting to $cm$: $1200\, cm 	imes 500\, cm 	imes 25\, cm = 15,000,000\, cm^3$. $2$. Calculate the volume occupied by the bricks: The mortar (sand and cement) occupies $5\%$ of the total volume,so the bricks occupy $95\%$ of the total volume. Volume of bricks $= 0.95 	imes 15,000,000\, cm^3 = 14,250,000\, cm^3$. $3$. Calculate the volume of one brick: Volume $= 25\, cm 	imes 12.5\, cm 	imes 7.5\, cm = 2343.75\, cm^3$. $4$. Calculate the number of bricks required: Number of bricks $= \frac{	ext{Volume of bricks}}{	ext{Volume of one brick}} = \frac{14,250,000}{2343.75} = 6080$.

Find the number of bricks,each measuring $25\, cm \times 12.5\, cm \times 7.5\, cm$,required to construct a wall $12\, m$ long,$5\, m$ high,and $0.25\, m$ thick,if the sand and cement mixture occupies $5\%$ of the total volume of the wall.

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