Find the gas,if its density at 273 K tempera | vedclass

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(C) The ideal gas equation is $PV = nRT$,which can be written as $PV = (m/M)RT$. Rearranging for density $(d = m/V)$,we get $d = (PM) / (RT)$. Given $

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$CO_2$

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(C) The ideal gas equation is $PV = nRT$,which can be written as $PV = (m/M)RT$. Rearranging for density $(d = m/V)$,we get $d = (PM) / (RT)$. Given $P = 76 \ cm \ Hg = 1 \ atm$,$T = 273 \ K$,$d = 1.94 \ g/dm^3$ (which is $1.94 \ g/L$),and $R = 0.0821 \ L \cdot atm \cdot K^{-1} \cdot mol^{-1}$. Substituting the values: $1.94 = (1 	imes M) / (0.0821 	imes 273)$. $M = 1.94 	imes 0.0821 	imes 273 \approx 43.5 \ g/mol$. The molar mass of $CO_2$ is $12 + 2 	imes 16 = 44 \ g/mol$. Thus,the gas is $CO_2$.

Find the gas,if its density at $273 \ K$ temperature and $76 \ cm \ Hg$ pressure is $1.94 \ g / dm^3$.

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